The major product formed in the following rea | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The reaction between $CH_3CHO$ (acetaldehyde) and $PhCOCH_3$ (acetophenone) in the presence of dilute $NaOH$ is a cross-aldol condensation reactio

Vedclass · Accepted Answer

$CH_3CH(OH)CH_2COPh$

Vedclass · Answer

(C) The reaction between $CH_3CHO$ (acetaldehyde) and $PhCOCH_3$ (acetophenone) in the presence of dilute $NaOH$ is a cross-aldol condensation reaction.$1$. Acetophenone has an $\alpha$-hydrogen atom,so it can form an enolate ion in the presence of a base $(NaOH)$.$2$. The enolate ion formed from acetophenone acts as a nucleophile and attacks the carbonyl carbon of the acetaldehyde $(CH_3CHO)$,which is more electrophilic than acetophenone.$3$. The nucleophilic attack leads to the formation of a $\beta$-hydroxy ketone.$4$. The reaction proceeds as follows:$PhCOCH_3 + OH^- \rightarrow [PhCOCH_2]^- + H_2O$$[PhCOCH_2]^- + CH_3CHO \rightarrow CH_3-CH(O^-)-CH_2-COPh$$CH_3-CH(O^-)-CH_2-COPh + H_2O \rightarrow CH_3-CH(OH)-CH_2-COPh + OH^-$Thus,the major product is $CH_3-CH(OH)-CH_2-COPh$.

The major product formed in the following reaction is:
$CH_3CHO + PhCOCH_3 \xrightarrow{\text{dil. } NaOH}$

Similar Questions

$A$ student is given one compound among the following compounds that gives a positive test with Tollen's reagent. The compound is:

The reaction of ethyl methyl ketone with $Cl_2$ / excess $OH^{-}$ gives the following major product:

Compound $(X)$ undergoes the following sequence of reactions to give the Lactone $(Y)$. Identify $(X)$.

What is the product obtained in the reaction of acetaldehyde with semicarbazide?

What reagent and/or reaction conditions would you choose to bring about the conversion shown in the image?

Vedclass Test Series

Exam Paper Generator

Online Exam Module

The major product formed in the following reaction is: $CH_3CHO + PhCOCH_3 \xrightarrow{\text{dil. } NaOH}$